Mean Perception Score and Indexing
Mean Perception Score
The mean perception score is calculated for each climatic zone of the pastureland for its pasture condition and the availability of forage grass (proxy for carrying capacity). Score is allotted as 1, 2, 3, and 4 for the pasture condition for very poor, poor, good, and very good respectively. Respondents were asked to choose one of the photographs which reflect the condition of their pastureland among the four photos. Conditions of pastureland were depicted in the photographs according to area coverage and the weeds and other infestation as well as soil erosion condition of the pastureland. Whatsoever, they pointed as the score for the pasture condition is recorded in as score. The mean perception score for each climatic zone is calculated as follow (Prof. Sharma, D.D).
Allotted score Frequency Total score
(a) (b) (c)= (a)(b)
Very good =4 0 4x0 = 0
Good =3 6 3x6 = 18
Poor =2 1 2x1 = 2
Very poor =1 3 1x3 =3
Total 10 23
Sum of total score
Now the mean perception score is given by, MPS= ------------------------- = 2.30
Some of frequency
As the herders are well acquainted with the animals in their field or pastureland conditions and they know better that how much animals has been fed on the pastureland they are grazing on. Similarly, mean perception score for forage grass availability of the pastureland is calculated. The forage availability score is developed by allotting score to the animals feed available up to 25 percent, 25 to 50 percent 50 to 75 percent and above 75 percent from the particular pastureland at that grazing period. The score as 1, 2, 3, and 4 is given as respondent responded to <25, 25-50, 50-75, and >75 percent respectively. And same procedure is followed to generate the mean perception score for forage grass availability of the pastureland.
Overall respondents’ perception percentage category can be calculated by forming the group categories as for “good; poor; and fair”. Here the mean value and standard deviation of the score in all climatic zones is used to represent the group in the question. It is done like this:
Good > mean + standard deviation
Poor < mean – standard deviation
Fair = mean +/- standard deviation
The score falling more than 3 with mean + standard deviation, less than 2 with mean 2 standard deviation, and between 2 and 3 are categorized as good, poor, and fair. Then the percentage of all falling to good, poor, and fair is calculated for the sample population.
Education Index
The education index of the sample family is calculated by giving a score as illiterate =0; primal level=1; middle level=2; high school=3; intermediate (or plus 2)=4 and graduate or above=5; and total score being 15. The index is calculated by dividing total sum of score (calculated by multiplying frequency of member with the score they got) with the total score. Example, for a family of four member having education level such as graduated person is one, illiterate is one, and two of them are in primary and middle level education, then the total score of the family is given by (1*5+1*0+1*1+1*2 = 8) and when divided by total score 15 the education index is 0.53 (=8/15).
Individual Index
For a given score the index value is supplied by following method.
If the score gained by a farmer is three and the score id provided by 1, 2, 3, and 4 to that particular category or variable say pasture condition or the forage availability from pasture, then the individual index of pasture condition is given by 3 out of 4 that is ¾ =0.75. Similarly for a person scored 2, then its index value is 2/4 that is 0.50. this method is applied in indexing the availability of forage grass from the pastureland.
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